I’ve done a little hunting with Digi Tech support. I’ll put what I’ve learned here for posterity.
Hi Tech Support,
I’m building a system of buoys to make measurements and relays to control equipment. These will communicate via DigiMesh using XBP9B-DMST-002 radios.
I’m evaluating a 3rd party as a hardware provider for a part of my buoy system. Have a look at
scroll mostly down to the bottom and you’ll see your radio. This board is a good fit in my system. I’ll use it to switch customer equipment on/off based on buoy sensing.
My plan is that the buoy will send commands by buoy Digi radio to relay board Digi radio. Relay will open/close.
But my buoy uses API mode. The relay uses Transparent mode. Bummer!
The relay board generates a response for every command it receives.
The buoy will know the MAC address of the relay board radio.
I’m not sure how the relay board will know the MAC address of the buoy
Will the relay board, DigiMesh, in transparent mode receive a TX Request (0x10) from the buoy?
If NOT, what can be done?
Will the relay board response arrive back at the buoy?
What frame will this response arrive in?
AT / Transparent mode and API mode only refer to the way in which the module interacts with the device connected to the module’s UART.
There are many networks in use that have an API master and AT/Transparent slave nodes. This is probably the most common setup we see.
In your case, having a mixed AT/API network should be fine.
A 0x10 frame send from an API transmitter will be received by the intended AT or API receiver. Once in the air, the packets are basically encoded in the same way.
I hope that answers your question.
Q: Will the relay board, DigiMesh, in transparent mode receive a TX Request (0x10) from the buoy?
A: Yes. Correct.
Q: Will the relay board transparent mode response arrive back at the buoy?
A: As long as the DH/DL of the transmitter in transparent mode matches the SH/SL of the receiver, then yes.
Q: What frame will this response arrive in?
A:The response will arrive as a Receive Packet frame 0x90.